cot∝=2÷3 . B=(3sin∝ + cos∝) ÷ (sin³∝-cos³∝)
cot∝=2÷3 . B=(3sin∝ + cos∝) ÷ (sin³∝-cos³∝)
Answer:
[tex]B=\frac{143}{19}[/tex]
Step-by-step explanation:
The explanation is attached below.
cot∝=2÷3 . B=(3sin∝ + cos∝) ÷ (sin³∝-cos³∝)
Answer:
[tex]B=\frac{143}{19}[/tex]
Step-by-step explanation:
The explanation is attached below.
0 Response to "cot∝=2÷3 . B=(3sin∝ + cos∝) ÷ (sin³∝-cos³∝)"
Post a Comment